There are two trains of 200m and 300m in length respectively. It is known that the speed of car a is 54km / h, and that of car B is 10m / S. (1) if the two trains run in opposite directions, what is the time from car a catching up with car B to staggering with car B? (2) If two vehicles are driving in the same direction, what is the time from car a catching up with car B to staggering with car B?

There are two trains of 200m and 300m in length respectively. It is known that the speed of car a is 54km / h, and that of car B is 10m / S. (1) if the two trains run in opposite directions, what is the time from car a catching up with car B to staggering with car B? (2) If two vehicles are driving in the same direction, what is the time from car a catching up with car B to staggering with car B?

V a = 54km / h = 15m / s, the distance of two vehicles passing each other s = s a + S B = 200m + 300m = 500m; (1) ∵ v = st, ∵ the time of two vehicles running in opposite directions: T1 = SV a + v b = 500m15m / S + 10m / S = 20s; (2) ∵ v = st, ∵ the time of two vehicles driving in the same direction: T2 = SV a − v b = 500m15m / s − 10m / S = 100s; (1) if two vehicles are running in opposite directions, the time from car a catching up with car B to staggering with car B (2) if two vehicles are driving in the same direction, the time from car a catching up with car B to staggering with car B is 100s

The length of the two trains is 270 meters. They both leave at a speed of 54 kilometers per hour. How many minutes does it take for the two trains to meet each other?

270×2÷1000÷（54×2）
=0.54÷108
=0.005 hours
0.005 hours = 0.3 minutes
So it takes 0.3 minutes from the meeting to the separation of the two trains

The two trains, a and B, set out at the same time from two places 500 kilometers apart and run in opposite directions. They meet in 2.5 hours. Car a is 40 kilometers faster than car B per hour. How many kilometers does car a travel per hour

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Set a car to travel x kilometers per hour
2.5（X+X-40）=500
2X-40=500÷2.5
2X-40=200
2X=240
X=120
Car a travels 120 kilometers per hour
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The distance between the two places is 480 km. The two cars of Party A and Party B leave each other at the same time. They meet four hours later. Train a is 8 km slower than train B every hour,
How many kilometers are the two columns

(480 △ 4 + 8) △ 2 = 64 (km / h) [b train speed]
(480 △ 4-8) △ 2 = 56 (km / h) [speed of train a]