Two ships a and B leave. A travels x kilometers, B travels 4 kilometers more than a, and they meet each other after t hours. A travels x kilometers, B travels 4 kilometers more than a, and t hours later Meet each other Express the distance between station a and station B with a formula containing letters If x = 40, t = 3, find the distance between stations a and B

Two ships a and B leave. A travels x kilometers, B travels 4 kilometers more than a, and they meet each other after t hours. A travels x kilometers, B travels 4 kilometers more than a, and t hours later Meet each other Express the distance between station a and station B with a formula containing letters If x = 40, t = 3, find the distance between stations a and B

Distance: S = t (2x + 4)
When x = 40, t = 3, s = 3 × (2 × 40 + 4) = 252km

There is a distance of 160 km between a and B in a river course. A and B ships are facing each other from a and B respectively. After 8 hours, they meet. At this time, a ship travels 64 km more than B ship
The two ships, a and B, respectively, are facing each other from a and B. after 8 hours, they meet each other. At this time, ship a travels 64 kilometers more than ship B, and the water speed is 1.5 km / h. The speed of ship a and B in still water can be calculated
50 points for quick and good answers

When we meet,
Ship a has gone: (160 + 64) △ 2 = 112 km
Ship B: 160-112 = 48 km
Per hour: 112 △ 8 = 14 km
B: 48 / 8 = 6 km per hour
We will discuss it in two ways
1) Ship a is in the water and ship B is against the water
The speed of ship a in still water is 14-1.5 km / h = 12.5 km / h
The speed of ship B in still water is 6 + 1.5 = 7.5km per hour
2) Ship a goes against the water, and ship B goes along the water
The speed of ship a in still water is 14 + 1.5 = 15.5km per hour
The speed of ship B in still water is 6-1.5 = 4.5km per hour
If the distance between a and B is 160 km, it means that a is upstream and B is downstream,
Then we only need to calculate according to the first case, and do not need to consider the second case

Two ships leave from the two wharves at the same time. One ship travels 24.6 kilometers per hour, the other 26.8 kilometers per hour. After 8.5 hours, the two ships meet
How many kilometers does a and B wharf meet

Distance between wharf A and wharf B = (24.6 + 26.8) × 8.5 = 51.4 × 8.5 = 436.9 km
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The river length of the two wharves is 90 km, and the two ships set sail from the wharves at the same time. If the two ships meet in the opposite direction for 3 hours, if the two ships catch up in the same direction for 15 hours, the speed of ship a overtakes that of ship B

The speed of ship a is 18 km / h
The speed of ship B is 12 km / h
Speed sum 90 / 3 = 30 km / h, speed difference 90 / 15 = 6 km / h,
Ship a's speed = (30 + 6) / 2 = 18 km / h, ship B's speed = (30-6) / 2 = 12 km / h