The speed ratio of a and B is 7:9. When they meet, a runs 240 meters less than B. how many meters away is ab

The speed ratio of a and B is 7:9. When they meet, a runs 240 meters less than B. how many meters away is ab

240÷(9-7)x(9+7)
=120x16
=1920 (m)

Party A and Party B travel from a and B at the same time. Party A travels 200 meters per minute and Party B 160 meters per minute. They meet at 80 meters from the midpoint______ Kilometers

The distance ratio between a and B: 200:160 = 5:4, 80 △ 12-45 + 4, = 80 △ 918-818, = 80 × 18, = 1440 (m); answer: A and B are 1440 km apart

Party A and Party B are facing each other from ab. 15 minutes later, they walk through the meeting point and leave for 120 meters. Party A's journey is complete
B. walk 25 meters per minute to find the distance between the two places

First, in 15 minutes, B walked 375 meters
15 minutes is 120 meters away
Therefore, a is 375-120m away from the end point = 255m
Because a takes only 25 minutes and has already walked for 15 minutes, there are still 10 minutes left,
So the speed of a is 255 meters, 10 minutes = 25.5 meters, no minutes
The distance is equal to the speed of a times the time of A
That is 25.5 * 25 minutes = 637.5

A and B are 240 meters apart. A and B are walking opposite each other. A walks 6 meters per second, B walks 4 meters per second. How many times do a and B meet in 15 minutes

Analysis: the first time a and B meet, they just walk 240 meters, so the time is 240 / (6 + 4) = 24 seconds
In the future, each encounter will take 240 * 2 = 480 meters, so the time is 480 / (6 + 4) = 48 seconds
15 minutes = 900 seconds
So there are (900-24) / 48 = 18 and 12
Therefore, Party A and Party B meet 18 + 1 = 19 times in 15 minutes
To sum up, Party A and Party B met 19 times in 15 minutes