AB is 30 kilometers away from each other. Party A and Party B face each other and meet each other in 2 hours and 30 minutes. If Party A starts for 2 hours first and Party B starts for 1 hour, how about the speed of Party A and Party B?

AB is 30 kilometers away from each other. Party A and Party B face each other and meet each other in 2 hours and 30 minutes. If Party A starts for 2 hours first and Party B starts for 1 hour, how about the speed of Party A and Party B?

Let a x, B y
2.5x+2.5y=30
3x+y=30
x=9 y=3

B's speed is two-thirds of a's. A and B set out from ab respectively. If they are facing each other, they will meet in an hour
If you go in the same direction, how many hours does it take for a to catch up with B?

If the velocity of a is V1, the velocity of B is 2 / 3v1
Let AB be the distance X
V1 + 2 / 3v1 = x
So AB = 5 / 3v1
It takes t hours for a to catch up with B
Then: 2 / 3v1 * t + AB = v1t
2/3V1*T+5/3V1=V1T
V1 is eliminated on both sides, so t = 5

The speed ratio of Party A and Party B is 3:2. Party A and Party B start from both places at the same time and walk in opposite directions. They meet in one hour and walk in the same direction. How long does it take for Party A to catch up with Party B

Beibeiqingqing,
Total distance:
（3＋2）×1＝5
In the same direction, a catches up with B:
5 ÷ (3-2) = 5 (hours)

Party A and Party B travel from AB, 28km away, and meet each other after 4 hours. If Party A walks 1km more than Party B per hour, then the speed of Party A is? That of Party B is? Urgent

Party A and Party B travel from AB, 28km away, and meet each other after 4 hours. If Party A walks 1km more per hour than Party B, then the speed of Party A is 4km / h and that of Party B is 3km / h