A and B start from a and B at the same time. They meet in 5 hours. When they meet, a walks 100 kilometers less than B, and a walks another 7.5 hours to B

A and B start from a and B at the same time. They meet in 5 hours. When they meet, a walks 100 kilometers less than B, and a walks another 7.5 hours to B

A is x km / h, B is y km / h
5 hours to meet. When meeting, a walks 100 kilometers less than B. 5 (Y-X) = 100
If a walks 7.5 hours to arrive at B, the 7.5 hour journey of a is that of B in 5 hours and the distance is 7.5x = 5Y
The two equations are x = 8 and y = 12
So the speed of a is 8 km / h, and the speed of B is 12 km / h

Party A and Party B set out from two places 38 kilometers apart by bike. They walked in Party A for 1.5 hours, and Party B met after walking for 2 hours. For the second time, they met from two teams at the same time
Starting, after 1 hour and 15 minutes, the distance is 10.5 kilometers. Find out the speed of a and B (with 2 yuan equation)

1 hour 15 minutes = 1.25 hours
Let a be x km / h and B be y km / h
1.5X+2Y=38
1.25（X+Y)=38-10.5
X = 12, y = 10
A: the speed of a is 12 km / h, and that of B is 10 km / h

A and B set out from a and B at the same time, facing each other. A just met B when a reached 100 meters past the midpoint. B walked 3 / 8 to find the distance?

100÷﹙1/2-3/8）
=100÷1/8
=800 (m)