When they set out, their speed ratio was 3:2. After their first meeting, a's speed increased by 20%, and B's speed increased by 30%. In this way, when a arrives at B, B is still 14 kilometers away from a, so how many kilometers is the distance between a and B?

Suppose the distance between a and B is SKM, and the speed of a and B is 3x and 2x respectively. When a and B meet for the first time, the distance they take is 3s5 = 0.6skm and 2s5 = 0.4skm respectively. According to the time series equation of a to B after meeting: 0.4s3x (1 + 20%) = 0.6s − 142x (1 + 30%), s = 45km. A: the distance between a and B is 45km

When they set out, their speed ratio was 3:2. After their first meeting, a's speed increased by 20%, and B's speed increased by 30%. In this way, when a arrives at B, B is still 14 kilometers away from a, so how many kilometers is the distance between a and B?

The ratio of the speed of B to that of a is 2:3. After they meet, they move on. A arrives at B and B arrives at a
It is known that the location of their second meeting is 20 kilometers away from the location of their first meeting, so how many kilometers is the distance between AB and ab

The speed ratio is 3:2
The distance ratio is 3:2
The distance of the first meeting is 3 / (3 + 2) = 3 / 5
The second time we met, Mr. A and Mr. B took three whole steps
A goes 3 / 5x3 = 9 / 5
At this time, 2-9 / 5 = 1 / 5 from a ground
20÷（3/5-1/5）＝20÷2/5＝50km
The distance is 50km

When they set out, their speed ratio was 3:2. After their first meeting, a's speed increased by 20%, and B's speed increased by 30%. In this way, when a arrives at B, B is still 14 kilometers away from a, so how many kilometers is the distance between a and B?