A and B set out from a and B at the same time, facing each other. When they set out, their speed ratio was 3:2. After they met for the first time, a's speed increased by 20%, B's speed increased by 30%. So when a arrives at B, B is still 14 kilometers away from A. what's the distance between a and B Don't explain, just use the formula Please, please

A and B set out from a and B at the same time, facing each other. When they set out, their speed ratio was 3:2. After they met for the first time, a's speed increased by 20%, B's speed increased by 30%. So when a arrives at B, B is still 14 kilometers away from A. what's the distance between a and B Don't explain, just use the formula Please, please

300t - (200t / 360) * 260 = 14, t = 9 / 100, so the distance: 500t = 45km,

A and B set out from a and B, respectively, and went opposite each other. When they set out, their speed ratio was 3:2. After they met for the first time, a's speed increased by 20%, and that of a's speed increased by 30%. In this way, when a arrives at B, B is still 14km away from a, so how many kilometers is the distance between a and B?
Formula

45 km

Party A and Party B set out from both places at the same time and walk opposite each other. The speed of Party A is 40 meters per minute, and that of Party B is 60 meters per minute. Three minutes after they meet, Party A goes to B to seek for Party A and Party B

(3*40 / 60) *(40+60) =200

Party A and Party B are facing each other from a and B. the speed of Party A is 100 meters per minute, and that of Party B is 120 meters per minute. After meeting for three minutes, how many meters is the distance between the two places
equation

I'm glad to answer your question
Let AB be x meters apart
（100+120）*3=x
220*3=x
660=x
x=660
A: the distance between AB and ab is 660 meters