A pile of coal, the first transport away two fifths, exactly 60 tons, the second transport away one fifth of the remaining coal, how many tons are left

A pile of coal, the first transport away two fifths, exactly 60 tons, the second transport away one fifth of the remaining coal, how many tons are left

Total = 60 △ 2 / 5 = 150 tons
Second transport = (150-60) * 1 / 5 = 18
Remaining = 180-18-60 = 72 tons

A pile of 60 tons of goods, the first time to use the total of 13, the second time to use the total of 25, how many tons of goods to share two times?

60 × (13 + 25), = 60 × 1115, = 44 (tons), a: 44 tons of goods are shared twice

For a pile of coal, two fifths will be transported away in the first time, and the remaining quarter will be transported away in the second time. At this time, there are still 30 tons left. How much coal was there

1-2/5=3/5
3/5×(1-1/4)=9/20
30 △ 9 / 20 = 200 / 3 ≈ 66.7 tons