There are two piles of coal. The first pile carries away 14 tons, and the second pile carries away part of the coal, leaving 60%. The weight ratio of the remaining first pile and the second pile is 3:5?

120 × (1-14), = 120 × 34, = 90 (T); 90 × 53 △ 60% = 150 △ 0.6, = 250 (T); answer: the original coal of the second pile is 250 t

There are two piles of coal. The weight ratio of the first pile to the second pile is 12:7. After being transported 1 / 4 from the first pile, the second pile is 36 tons less than the first pile. How many tons of coal was there in the first pile

Set the first pile of X tons and the second pile of Y tons
X：Y=12:7
3/4X-Y=36
Solving equations
X=216
Y=126

There are two piles of coal. The second pile is 2.5 times of the first pile. If 3.6 tons are taken out of the second pile and put into the first pile, the weight of the two piles of coal is equal. How many tons of each pile of coal?

Suppose one pile weighs x tons, then the other pile weighs 2.5x tons, 2.5x-3.6 = x + 3.62.5x-x = 7.21.5x = 7.2x = 4.82.5x = 12, that is, one pile weighs 4.8 tons, then the other pile weighs 12 tons. The formula is: 3.6 * 2 ÷ (2.5-1) = 4.84.8 * 2.5 = 12! If you are satisfied, don't forget to adopt it. For more information, click www.baidu.com/p/w...

There are two piles of coal. The weight of the second pile is 2.5 times of that of the first pile. If 3.6 tons of coal is taken out of the second pile and put into the first pile, the weight of the two piles of coal is equal, and the two piles of coal are in good condition

Suppose the first pile of coal is x tons and the second pile is 2.5x tons
2.5x-3.6=x+3.6
The solution is x = 4.8
The first pile of coal is 4.8 tons, and the second pile of coal is 4.8 * 2.5 = 12 tons

There are two piles of coal. The first pile carries away 14 tons, and the second pile carries away part of the coal, leaving 60%. The weight ratio of the remaining first pile and the second pile is 3:5?