The two piles of coal a and B are equal. A transports 25 tons, B transports 17 tons, a surplus: B surplus = 13:15, how many tons did a and B originally have It's better to use fractions or fractions instead of equations

The two piles of coal a and B are equal. A transports 25 tons, B transports 17 tons, a surplus: B surplus = 13:15, how many tons did a and B originally have It's better to use fractions or fractions instead of equations

Analysis: because "the two piles of coal of a and B are equal", and know that a has transported more than B: 25-17 = 8 tons, at this time, the remaining shares of a are less than B: 15-13 = 2, then, the remaining each share has: 8 △ 2 = 4 tons, so, a's remaining: 4 × 13 = 52 tons, B's remaining: 4 × 15 = 60 tons, a's original total: 25 + 52 + 17 + 60 = 154 tons

There are two piles of coal. There are 20 tons of coal in pile a and 17.5 tons of coal in pile B. 2 tons of coal in pile a and 1.5 tons of coal in pile B are used every day. After how many days, the remaining tons of coal in the two piles are similar

If 20-2x = 17.5-1.5x, then 0.5x = 2.5x = 5, i.e. 5 days

A, B two piles of coal, tonnage ratio is 5:3, from a transport of 90 tons to B, a and B tons are equal, find a and B original coal how much?

Specific process:
Suppose the tonnage of a is 5x tons and that of B is 3x tons
5X-90=3X+90
2X=180
X=90
So 5x = 450, 3x = 270
A: 450 tons for a and 270 tons for B

For a batch of cement, car a can transport one tenth of this batch of cement at a time, and car B can transport one fifteenth of this batch of cement at a time
Can we finish this batch of cement? Please write down the formula and explain the reason

(1/10+1/15)×6=1
So it's just finished