There are two barrels of oil a and B. barrel a weighs three thousand grams more than barrel B. now take two seventh of a kilogram from barrel a and pour it into barrel B. barrel a weighs thousands more than barrel B There should be a formula

There are two barrels of oil a and B. barrel a weighs three thousand grams more than barrel B. now take two seventh of a kilogram from barrel a and pour it into barrel B. barrel a weighs thousands more than barrel B There should be a formula

If the oil in barrel a is x g, and the oil in barrel B is y g, then X-Y = 3 / 4, take two seventh of a kilogram from barrel a and pour it into barrel B, then the oil in barrel a is X-2 / 7, and the oil in barrel B is y + 2 / 7. Then the oil in barrel a is heavier than that in barrel B: X-2 / 7 - (y + 2 / 7) = X-Y-4 / 7

There are two barrels of oil, one kilogram for a and one kilogram for B. If one eighth of a barrel is poured into B barrel, and the two barrels are equal, how many kilograms for a and B?

A: B
=1：1-1/8-1/8
=1：6/8
=4：3
A = 1 △ (4 + 3) × 4 = 4 / 7 kg
B = 1-4 / 7 = 3 / 7 kg

The total weight of a and B barrels of oil is 54 kg. Two fifths of a barrel of oil is poured out and 6 kg of B barrel of oil is poured out

10 kg. Let B be x kg. Then a is 5x / 2 kg (x + 5) / (5x / 2 - 5) = 3 / 4 x =? Calculate

If the oil in barrel B is injected into barrel a for 20 kg, the oil in barrel a is three times that in barrel B, and the oil in barrel a is the same as that in barrel B______ Kg, B barrel of original oil______ Kilogram

160 ÷ (1 + 3) = 40 (kg), the injected barrel a: 3 × 40 = 120 (kg), the poured barrel B: 1 × 40 = 40 (kg), the original barrel a: 120-20 = 100 (kg), the original barrel B: 40 + 20 = 60 (kg), a: the original barrel a: 100 kg, the original barrel B: 60 kg

The weight of barrel a is 4.8kg more than that of barrel B. after taking out 2.4kg each, 3 / 11 of barrel a's oil is equal to 1 / 3 of barrel B's oil?

If the weight of oil in B tank is XKG, the weight of oil in a tank is (4.8-xkg)
(x-2.4)*3/11=[(4.8-x)-2.4]*1/3
x=2.4
4 = 2. 4
Now there are: a oil barrel: 2.4kg, B oil barrel: 0kg

A and B have a total oil weight of 40 kg. After pouring 1 / 6 of a barrel into B barrel, the weight ratio of a and B is 3:5. How many kg are the original A and B?

If a has oil x, B has 40-x
After pouring 1 / 6 of a barrel to B barrel
Then a has x (1-1 / 6) = 5x / 6, B has 40-x + X / 6 = 40-5x / 6
There are
5X/6:(40-5X/6)=3:5
5 (5x / 6) = 3 (40-5x / 6) multiply by 6
5*5X=3*(40*6-5X)=720-15X
25X+15X=720
X=18
40-X=22

The mass ratio of the first oil tank to the second oil tank is 5:6. Pour 55 kg oil into the first oil tank, and the mass ratio of the second oil tank to the original oil is 2:3
At this time, the two barrels of oil are the same weight. How many kilograms did the two barrels of oil weigh?

If the original mass of barrel a is 5x, the original mass of barrel B is 6x
From the title: the quality of a barrel after oil is 5x + 55
The quality of oil in B barrel is 6x + (6x × (2 / 3))
From the meaning of the title: 5x + 55 = 6x + (6x × (2 / 3))
5x+55=6x×（5／3）
5x+55=10x
x=11
So answer: a barrel originally weighs 55 kg, B barrel originally weighs 66 kg

There are two barrels of oil. Barrel a oil is 15 kg less than barrel B oil. Now pour 125 of barrel B oil into barrel A. at this time, barrel a oil is 5 kg more than barrel B oil. How many kg of barrel B oil was there?

(15 + 5) / (125 × 2) = 20 / 225 = 250 (kg) a: B barrel oil used to be 250 kg

There are two barrels of oil. Barrel a weighs 7 / 8 kg more than barrel B. now take 1 / 4 kg from barrel a and pour it into barrel B. at this time, the oil in barrel a is heavier than that in barrel B
How many kilos does it weigh?

7/8-(2×1/4)
=3/8

There are two piles of coal a and B, 12 tons of which are taken out of a and put into B, and the weight of the two piles is equal; 12 tons of which are taken out of B and put into a, and the weight of a is twice that of B______ Tons

If the original x tons of coal in pile B is set, then the coal in pile a has x + 12 × 2 tons. According to the meaning of the problem, the equation can be obtained as follows: x + 12 × 2 + 12 = 2 (X-12), & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X + 36 = 2x-24, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 60, 60 + 12 × 2 + 60 = 144 (tons)