A pile of coal, originally planned to burn 3 tons a day, can burn 96 days. In fact, 2.4 tons a day, how many days can actually burn? (answer in proportion)

A pile of coal, originally planned to burn 3 tons a day, can burn 96 days. In fact, 2.4 tons a day, how many days can actually burn? (answer in proportion)


It can burn for X days. 3 × 96 = 2.4x & nbsp; & nbsp; X = 3 × 962.4 & nbsp; & nbsp; & nbsp; X = 120 A: it can burn for 120 days



A factory has stored 50 tons of coal. Due to the improvement of stove and coal burning technology, 2 tons of coal can be saved every day, and the stored coal can be used 20 days more than the original plan. How much coal is the original plan to burn every day


It was originally planned to burn x tons of coal a day
50 / X is the original 50 tons of coal can burn days
50 / (X-2) is the number of days that can be burned now
On the equation of 50 / x + 20 = 50 / (X-2)
The solution is: x = 1 + radical 6 or 1-radical 6 (rounding off)
A: Yes



The factory transported a batch of coal, planned to burn 3 tons a day, burned it out in 60 days, and actually burned it for 45 days. How many tons more than originally planned?


3x60 = 180 tons 180 △ 45 = 4 tons 4-3 = 1 ton
So burn an extra ton



The factory has 8000 kg of coal, which was originally planned to burn for 25 days. Due to the improvement of the stove, it actually burned for 32 days. How many kg is saved per day on average compared with the original plan?


8000 / 25-8000 / 32 = 320-250 = 70 (kg) a: on average, it saves 70 kg per day compared with the original plan



The school sent a batch of coal. In January, it burned all 23 tons less than 1 ton. In February, it burned the remaining 25 tons more than 1 ton. At this time, there are still 4 tons left. How many tons of this batch of coal are there?


[(4 + 1) / (1 − 25) - 1] / (1 − 23) = [5 − 35-1] / - 13, = [5 × 53 − 1] / - 13, = [253 − 1] / - 13, = 223 − 13, = 223 × 3, = 22 (T); a: this batch of coal is 22 t



There are 36 tons of coal in the freight yard, and there are three trucks with different carrying capacity. How can we just load them with trucks and transport them at least? Car 1 car 2 car 3 car 2 ton 3 ton 5 ton


36 △ 5 = 7 times 1 ton, so use a 5-ton truck, transport 7 times, then the remaining 1 ton, no matter which kind of truck is used, can't be loaded exactly. So use a 5-ton truck to transport 6 times, and there are 36-5 × 6 = 6 tons left. Then use a 3-ton truck to transport 6 times, and then use a 3-ton truck to transport 2 times. A: use a 5-ton truck to transport 6 times, and then use a 3-ton truck to transport 2 times



A batch of coal is transported to 1 power plant. It is planned to burn 3 / 2 tons of coal every day, which can burn 35 days. In fact, it saves 0.25 tons of coal every day compared with the plan. How many days has this batch of coal actually been burned? (use the equation)
Team a completed 62% of the total length of the road, 360 meters more than team B. how many meters is the total length of the road?
25% of 3a is equal to 2 / 5 of B. the ratio of a to B is ()
4:32 = () (fill in the score)
Two adjacent numbers must be coprime numbers (judgment)
6 A is 10 times of B, B is 1 / 10 of A
Write why


A batch of coal is transported to 1 power plant. It is planned to burn 3 / 2 tons of coal every day, which can burn 35 days. In fact, it saves 0.25 tons of coal every day compared with the plan. How many days has this batch of coal actually been burned? (use the equation)
Suppose that the coal actually burned for X days
(3/2-0.25)X=3/2*35
X=42
Team a completed 62% of the total length of the road, 360 meters more than team B. how many meters is the total length of the road?
360/[62%-(1-62%)]=1500
25% of 3a is equal to 2 / 5 of B. the ratio of a to B is (8 / 5)
4:32 = (8 / 4,15) (fill in the score)
5 two adjacent numbers must be coprime (√)
6 A is 10 times of B, B is 1 / 10 of a (√)



A batch of coal is transported to the power plant. It is planned to burn 1.5 tons a day, which can burn for 35 days. In fact, it saves 0.25 tons a day compared with the plan. How many days can this batch of coal actually be burned?


Suppose that it can burn for X days
X*(1.5-0.25)=1.5*35
1.25X=52.5
X=52.5/1.25
X=42
It can be burned for 42 days



When a batch of coal is transported to the power plant, it is planned to burn 1.2 T / day, which can last 25 days. In fact, it is planned to save 1.25 T / day. How many days has this batch of coal actually been burned? (in proportion)


When a batch of coal is transported to the power plant, it is planned to burn 1.2 T / day, which can last 25 days. In fact, it is planned to save 1.25 T / day. How many days has this batch of coal actually been burned? (in proportion)
Let's suppose that the actual burning time is x days
1 and 1 / 2 tons = = 1.5 tons
(1.5-1.25)X==1.5*25
X==1.5*25/0.25
X==150
A: this batch of coal actually burned for 150 days



Dongfeng Power Plant has delivered a batch of coal, which is planned to burn 1.5 tons per day, and can burn for 35 days. In fact, it saves 0.25 tons per day compared with the plan, and this batch of coal can actually be burned
How many days?


1.5 × 35 ÷ (1.5-0.25) = 42 days
A: it can be burned for 42 days