The structure of an organic compound is determined: the mass fraction of carbon of the organic compound containing Cho is 64.86%, and the mass fraction of hydrogen is 13.51%. Q: what is the molecular formula? There's a mass spectrum that hasn't been transmitted

The structure of an organic compound is determined: the mass fraction of carbon of the organic compound containing Cho is 64.86%, and the mass fraction of hydrogen is 13.51%. Q: what is the molecular formula? There's a mass spectrum that hasn't been transmitted

(1) , 1 - (64.86% + 13.51%) = 21.63%, which is the mass fraction of O;
（2）、64.86/12：13.5/1：21.63/16=5.4：13.5：1.35=4：10：1；
(3) The molecular formula is c4h10o

The relative molecular weight of an organic compound is close to each other. It contains 64.87% of carbon, 13.51% of hydrogen and 21.62% of oxygen by combustion measurement
Thank you for your trouble!
Please write down the process.

According to the results, the organic compound only contains C, h and O. it can be assumed that its chemical formula is C (x) H (y) O (z), then 12x: Y: 16Z = 64.87%: 13.51%: 21.62% (the origin of this formula is that according to the ratio of its mass fraction, the three expressions on the left should be divided by 12x + y + 16Z

There are two granaries A and B. the rice stored in warehouse A is 25% less than that in warehouse B. If 8 tons of rice are put into warehouse A from warehouse B, there will be as much rice in warehouse A as in warehouse B
How many tons of rice are there in each of the two warehouses?

8*2=16t
A16 / 25% = 64t
B 64 * (1-25%) = 48T

There are 300 tons of rice in granaries A and B. if 60% of the rice is transported from granary a to granary B, the ton of rice in granary B is twice that of the remaining ton of rice in granary a,
How many tons of rice were there in a and B granaries

A warehouse now has: 300 (1 + 2) = 100 tons
B warehouse now has: 300-100 = 200 tons
Original warehouse A: 100 (1-60%) = 250 tons
Original warehouse B: 300-250 = 50 tons

There are more than 200 bags of rice in granary A and B than in granary B. If granary B delivers 150 bags to granary a, the existing rice is three times as much as the remaining rice in granary B, how many bags of rice are there in granary A and B

There are three equations
A: x B: y
x+y=y+200
We get x = 200
3x=y-150
The result is y = 750

There are rice in granary A and B. the number of rice bags in granary A and B is 7:5. If 120 Bags of rice are transported from granary a to granary B, and the number of rice bags in the two granaries is equal, how many rice bags did each granary A and B have?

7÷﹙7＋5﹚＝7/12
120 (7 / 12-1 / 2) = 1440 bags
Warehouse A: 1440 × 7 / 12 = 840 bags
Warehouse B: 1440 × 5 / 12 = 600 bags

There are 20 bags more rice in warehouse A than in warehouse B. If 150 bags are transported from warehouse B to warehouse A, which is three times of the remaining rice in warehouse B, how much is the original quantity in warehouse a

There are 20 bags more rice in warehouse A than in warehouse B. If 150 bags are transported from warehouse B to warehouse A, it is warehouse B now. At this time, warehouse A has 150 + 150 + 20 bags more than warehouse B = 320 bags
Now B has 320 (3-1) = 160 bags
B originally had 160 + 150 = 310 bags
A had 310 + 20 = 330 bags

Mathematics: the weight ratio of goods in warehouse A and warehouse B is 9:7. If warehouse a delivers 10 tons to warehouse B, warehouse a will be 6 tons less than warehouse B
How many tons, don't use the equation

A is 10x2-6 more than B = 14T
A: original 14x9 (9-7) = 63 tons
B: 63-14 = 49 tons

Take out 1 / 5 of the weight of grain from warehouse A and transport it to warehouse B, which means that the weight of grain in the two warehouses is the same. Then the weight comparison of grain in the two warehouses

5:3

Zhang Liang's pocket money is 5 / 9 of Huang Ming's. in the charity activities, Huang Ming donated 48 yuan and Zhang Liang donated 20 yuan. At this time, they have the same amount of pocket money left
I want the formula
It's better to have an analysis

Huang Ming donated 28 yuan more than Zhang Liang
Corresponding to 4 copies
Zhang Liang's is 5, Huang Ming's is 9
28/4=7
Zhang Liang 7 * 5 = 35
Huang Ming 7 * 9 = 63