A and B both leave from two stations 360 km apart at the same time. Car a travels 50 km per hour, 25% faster than car B. a few hours later, the two cars meet?

360 ^ [50 ^ (1 + 25%) + 50], = 360 ^ [50 ^ [125% + 50], = 360 ^ [40 + 50], = 360 ^ [90, = 4 (hours), a: the two cars meet in 4 hours

Car a and car B leave from two places 360 kilometers apart at the same time. After 2.4 hours, they meet. The speed of car a is 1.4 times that of car B. how many kilometers is car a from the destination when they meet? (use the equation to solve)

If the speed of vehicle B is x km / h, the speed of vehicle a is 1.4x
Then 360 / (x + 1.4x) = 2.4
The solution is x = 62.5
The speed of car a is 62.5 * 1.4 = 87.5km/h

A and B trains leave from two places at the same time and meet each other after 4 hours. It is known that a train travels 65 kilometers per hour
B car travel 55 kilometers per hour, find the distance between the two places

Distance between the two places = (65 + 55) × 4 = 120 × 4 = 480 (km)
A: the distance between the two places is 480km

Car a and car B travel from a and B at the same time. Car a travels 55 kilometers per hour and car B 45 kilometers per hour
Car a and car B travel from a and B at the same time. Car a travels 55 kilometers per hour and car B 45 kilometers per hour. After the two cars are 10 kilometers away from the midpoint, how long after car a arrives at point B and how long after car B arrives at point a?

Meeting time
10x2 ÷ (55-45) = 2 hours
The distance between the two places is 2x (55 + 45) = 200 km
200÷45-200÷55
=40/9-40/11
=80 / 99 hours
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A and B both leave from two stations 360 km apart at the same time. Car a travels 50 km per hour, 25% faster than car B. a few hours later, the two cars meet?