The two cars start from two places 298km apart and run towards each other at the same time. The speed of car a is 20km / h faster than that of car B. half an hour later, the two cars meet. What are the speeds of the two cars?

Suppose the speed of car B is XKM / h, then the speed of car a is (2x + 20) km / h. according to the title, we get 12 (2x + 20) + 12x = 298, and the solution is x = 192.2x + 20 = 2 × 192 + 20 = 404. A: the speed of car a is 404km / h, and that of car B is 192km / h

A and B two cars from AB two opposite, a car than B car started 15 minutes earlier
A and B two cars from a, B two opposite, a car than B car started 15 minutes earlier, a, B two car speed ratio is 2:3, meet, a less than B walk 6 km, B walk 1 hour 30 minutes, find a and B speed and distance between two places! To use one yuan equation solution!

Suppose: the speed of car a is x, and the unit is km / h 15 minutes = 0.25h 1 hour 30 minutes = 1.5h. As it is known that car B has driven for 1.5 hours, car a is 0.25 hours earlier than car B, and the driving time of car a is 1.5 + 0.25 = 1.75h, and the speed of car B is x / 2 * 3 = 1.5x, so: 1.75 * x + 6 = 1.5 * 1.5x1.75x + 6 = 2.25x6 = 0.5xx = 12 km /

The speed of car a is 20 km / h faster than that of car B
Half an hour later, the two cars meet. What's the speed of the two cars?

If the speed of car B is x, then the speed of car a is x + 20
1/2(x+x+20)=298,
The solution is x = 288
(but the speed of the car is 288km / h, which is not in line with the reality. Please check the original question.)