The distance between a and B is 270km. The local train starts from home at the speed of 50km / h, and the express train starts from B at the speed of 60km / h. The two trains are facing each other The slow train leaves for 1.5 hours. How many hours after the slow train leaves, the two trains will meet? The "equation" writes out everything set!

The distance between a and B is 270km. The local train starts from home at the speed of 50km / h, and the express train starts from B at the speed of 60km / h. The two trains are facing each other The slow train leaves for 1.5 hours. How many hours after the slow train leaves, the two trains will meet? The "equation" writes out everything set!

The two trains meet after the slow train leaves for X hours
50X+60x（X-1.5)=270
50X+60X-90=270
110X=270+90
X=36/11

The two cars leave from two places at the same time and meet each other in three hours. The speed ratio of car a and car B is 5:4, and the distance between the two places is 270km

270 △ 3 = 90 (km), 5 + 4 = 9, 90 × 59 = 50 (km), 90 × 49 = 40 (km). A: the speed of car a is 50 km / h, and that of car B is 40 km / h

The two cars leave from two places at the same time and meet each other in three hours. The speed ratio of car a and car B is 5:4, and the distance between the two places is 270km

270 △ 3 = 90 (km), 5 + 4 = 9, 90 × 59 = 50 (km), 90 × 49 = 40 (km). A: the speed of car a is 50 km / h, and that of car B is 40 km / h

The two cars leave from two places at the same time and meet in three hours. The speed ratio of car a and car B is 5:4. The distance between the two places is 270km. What's the speed of the two cars?
Total speed of two vehicles = 270 / 3 = 90 km / h
Car a = 90 * (5 / 9) = 50 km / h
Vehicle B = 90 * (4 / 9) = 40 km / h
The speed of the two cars is 50 km / h and 40 km / h respectively

Let car a be 5x and car B be 4x
3*（5x+4x）=270
x=10
So a is 50km / h, B is 40km / h