The speed ratio of the two vehicles is 5:7. After meeting, the two vehicles continue to run at the original speed Go ahead. When car B arrives at place a, car a is 48 kilometers away from place B. how many kilometers did car B travel after meeting

The speed ratio of the two vehicles is 5:7. After meeting, the two vehicles continue to run at the original speed Go ahead. When car B arrives at place a, car a is 48 kilometers away from place B. how many kilometers did car B travel after meeting

In the whole process, car B finished the whole journey, and car a's speed was 5 / 7 of car B's, so car a took 5 / 7 of the total journey
The total distance is 48 / (1-5 / 7) = 168 km
The distance of car B after meeting is equal to the distance of car a before meeting, that is, 5 / 12168 * 5 / 12 of the total distance = 70km

A and B leave from ab at the same time and meet in 40 minutes. After meeting, they continue to move forward at the same speed. B arrives at the terminal of AB in 5 minutes and a
How many parts of the whole journey does the car travel per minute
A passenger car and a freight car leave from a and B at the same time. After six hours of meeting, the two cars continue to move forward at the same speed. After another 4 hours of bus B, this is the truck, 188 kilometers away from a. How many kilometers are the two places apart? No, thank you

It takes 90 minutes for car B to complete the whole journey, 40 / 90 = 4 / 940 minutes for car a to complete the whole journey, 1-4 / 9 = 5 / 9 for car a, and 40 / (5 / 9) = 72 minutes for car a to complete the whole journey, so car a takes 1 / 72 every minute. That's the 6-hour journey for freight cars and 4-hour journey for passenger cars, so the speed of freight cars is that of passenger cars: 4 △ 6 = 2

A car and a motorcycle leave from a and B at the same time. After 5 hours of meeting, both cars continue to move at the same speed. After another 3 hours, the car arrives at B. the motorcycle is 120 kilometers away from B. how many kilometers are there between a and B?

If the car travels x kilometers per hour, the motorcycle travels 3x / 5 = 0.6x per hour
5X=3*0.6X+120
3.2X=120
X=37.5
Distance between a and B = 37.5 * 8 = 300

The ratio of walking speed between a and B is 7:5. They set out from a and B at the same time and walk in opposite directions. They met at 0.5 hours
The walking speed ratio of a and B is 7:5. They start from a and B at the same time and walk in opposite directions. They meet after 0.5 hours. If they start from a and B at the same time and walk in the same direction (one is in a and the other is in B, but they all face the same direction), then it will take a few hours for a to catch up with B (answer the equation!)
Xiao Li goes from a to B by bike, and Xiao Ma Na goes from B to a by bike. They go at a constant speed. It is known that they set out at 8 am at the same time. By 10 am, they are still 36 km apart. At 12 noon, they meet again for 36 km. The AB distance is calculated (also using the equation)
Answer the equation once a dollar!

1. Suppose that a's walking speed is x km / h. because the ratio of the walking speed of a and B is 7:5, B's walking speed is 5 / 7X km / h. therefore, the distance between a and B (that is, the distance difference between a and B in the same direction) is: (x + 5 / 7X) 0.5 = 6 / 7X. The time that a needs to catch up with B is t hour, so a and B need to walk