If you use the same car to transport the goods out of the warehouse, if you use four cars a day, it will be finished in nine days; if you use five cars a day, it will be finished in six days. If you use one car to transport the original inventory in the warehouse, how many days will it take?

If you use the same car to transport the goods out of the warehouse, if you use four cars a day, it will be finished in nine days; if you use five cars a day, it will be finished in six days. If you use one car to transport the original inventory in the warehouse, how many days will it take?

Suppose that each vehicle transports goods every day as the unit "1", the daily purchase quantity: (4 × 9-5 × 6) / (9-6) = 2; the original goods in the warehouse: 4 × 9-2 × 9 = 18; that is, if the original stock in the warehouse is transported by one vehicle for 18 days, it can be exactly completed. & nbsp; answer: it takes 18 days to complete the transportation

To transport 840 tons of goods, the task is assigned according to the number of cars in the transport team. Team a has 12 cars, team B has 16 cars, and team C has 14 cars. How many tons of goods should each of the three teams transport?

840÷（12+16+14）=840÷42=20
A 12 × 20 = 240
B 16 × 20 = 320
C 14 × 20 = 280

The master worker is going to transport 22 tons of steel from the warehouse to the construction site. If he rents a 3-ton car, the freight of each car is 140 yuan. If he rents a car with a load of 4 tons
The freight of each car is 200 yuan. How to rent a car with less freight? How much does it cost at least

Hello
For a 3-ton car, the freight per ton is about:
140 △ 3 ≈ 46.67 (yuan)
For a 4-ton car, the freight per ton is about:
200 △ 4 = 50 (yuan)
So it's more cost-effective to use more 3 tons of cars, and the freight is less
22 tons = 3 tons × 6 + 4 tons × 1
So, rent 6 3 tons car and 1 4 tons car freight at least
At least:
140 × 6 + 200 = 1040 yuan

The distance between car a and car B is 120km. Car a travels 48km per hour and car B 60km per hour
1. If car a is in the prelude of car B, ask how many hours later Party B will catch up with car a and solve the equation with one variable
2. If car a is behind car B, ask how many hours the two cars meet 180 km, and solve the equation with one variable

The distance between car a and car B is 120km. Car a travels 48km per hour and car B 60km per hour
1. If car a is in the prelude of car B, ask how many hours later Party B will catch up with car a and solve the equation with one variable
Let's catch up in X hours
(60-48)x=120
12x=120
x=10
2. If car a is behind car B, how many hours is the distance between the two cars 180km? Solve the equation with one variable
The distance is 180 km in X hours
(60-48)x=180-120
12x=60
x=5