There are 195 cars in the two stations. If 36 cars are driven from station a to station B and 45 cars are driven from station B, the number of cars in station B is twice that in station A. how many cars are there in station a and station B?

There are 195 cars in the two stations. If 36 cars are driven from station a to station B and 45 cars are driven from station B, the number of cars in station B is twice that in station A. how many cars are there in station a and station B?


Now station a: (195-45) / (1 + 2) = 50 (vehicles), the original station a: 50 + 36 = 86 (vehicles), the original station B: 195-86 = 109 (vehicles), a: the original station a parking 86 cars; station B parking 109 cars



A car goes from place a to place B and stops 40 kilometers away from the midpoint to refuel. At this time, the remaining distance is 20% less than what it has already traveled. How many kilometers is the distance between the two places
fast


Let AB be x km apart, then (x / 2 + 40) * 80% = x / 2-40, x = 720, so AB is 720 km apart



A and B leave from AB, and it takes 5 hours for a to finish the whole journey, and 4.5 hours for B to drive. How many hours do they meet?
There are: encounter B than a line more than 25kmab?
These are two questions
I gave it 100 points


Let the distance be s
Speed a = s / 5
Speed B = s / 4.5
Relative open, time = s / (speed a + speed b) = 1 / (1 / 5 + 1 / 4.5)
=1 / (9 / 45 + 10 / 45) = 45 / 19 = 2.36842 hours
At this time, the distance a travels is speed * time
= S/5*45/19 = S * 9 / 19
The distance of B is s / 4.5 * 45 / 19 = s * 10 / 19
The difference is s / 19 If the difference is 25 km
So s = 25 * 19 = 475 km



A and B start from two places and run in opposite directions. At 2.5 o'clock, they meet at 20 kilometers away from the midpoint. A car runs 80 kilometers per hour. What's the speed of B car?


A and B start from two places and run in opposite directions. At 2.5 o'clock, they meet 20 kilometers from the midpoint,
A car 80 km / h, driving 2.5 x 80 = 200 km
Driving distance of vehicle B = 200 + (20x2) = 240km or 200-40 = 160km
Find the speed of car B = 240 / 2.5 = 96 or 160 / 2.5 = 64