After braking, a stops 36m ahead within 3S, and B stops after 1.5s, then B advances

After braking, a stops 36m ahead within 3S, and B stops after 1.5s, then B advances

The initial velocity is the same as the final velocity, and the average velocity is the same
So B goes 18 meters

After braking at the same time, the two vehicles of a and B are moving in a straight line with uniform deceleration. A stops for 3 seconds and advances for 36 meters. B stops for 1.5 & nbsp; s. The forward distance of B is ()
A. 9 mB. 18 mC. 36 mD. 27 m

The ratio of the velocity of the object which starts to do uniform acceleration motion from the static state at the end of 3S to the end of 5S is______ The ratio of displacement in 3S to that in 5S is______ The ratio of displacement in 3S to that in 5S is______ ．

According to v = at, the ratio of velocity at the end of 3S to that at the end of 5S is 3:5. According to x = 12at2, the ratio of displacement in 3S to that in 5S is 9:25 The displacement ratio is 1:4:9 N 2, then in the first second, the second and the third seconds The displacement ratio is 1:3:5 (2n-1), so the ratio of displacement in 3S and 5S is 5:9. So the answer is: 3:5, 9:25, 5:9

Party A and Party B run the 100 meter race. When Party A reaches the finish line, Party B is still 10 meters away. If Party A is allowed to retreat 10 meters from the starting line, who will get there first?
Explain in a scientific way

A should come first
A runs 110 meters,
B ran 110 × (100-10) / 100 = 110 × 9 / 10 = 99 meters
So it's a who gets to the end first