A passenger train is 200 meters long and a freight train is 280 meters long. They run in opposite directions on parallel tracks. After 15 seconds from meeting to leaving at the end of the train, the speed ratio of the passenger train to the freight train is lower 5: 3. Ask how many meters each car travels per second

A passenger train is 200 meters long and a freight train is 280 meters long. They run in opposite directions on parallel tracks. After 15 seconds from meeting to leaving at the end of the train, the speed ratio of the passenger train to the freight train is lower 5: 3. Ask how many meters each car travels per second

Driving: 200 + 280 = 480 meters
The speed sum of the two cars is 480 △ 15 = 32 meters per second
therefore
The speed of the bus is 32 × 5 / (5 + 3) = 20 meters per second
The speed of the truck is: 32 × 3 / (5 + 3) = 12 meters per second
I wish you progress in your study

A passenger train is 200 meters long and a freight train is 280 meters long. They run in opposite directions on parallel tracks. After 18 seconds, when the speed ratio of the passenger train to the freight train is 5:3, the freight train runs every hour______ Kilometers

Suppose that the speed of a freight car is x meters per second and that of a passenger car is 53x meters per second. From the meaning of the question, we get (x + 53x) × 18 = 200 + 280, and the solution is x = 10. That is, the speed of a freight car per hour is 10 × 3600 △ 1000 = 36 (km). So the answer is: 36

The speed of a passenger car is 60 km / h, and that of a train is 45 km / h. The freight car is 105 meters longer than the passenger car. If two cars are running on parallel tracks
When a passenger car catches up with a freight car from behind, the time for them to meet (i.e. from the moment when the front of the passenger car catches up with the rear of the freight car to the moment when the rear of the passenger car leaves the front of the freight car) is 1 minute and 30 seconds. (1) find the length of two cars; (2) if two cars are facing each other, what is the crossing time?
It's better to use the formula! The formula is not good, and the equation is OK

(1) 60 km / h = 50 / 3 M / S
45 km / h = 12.5 M / S
Length of two cars = (50 / 3-12.5) * 90 = 375 (speed difference multiplied by time = distance)
(2) 375 / (50 / 3 + 12.5) = 90 / 7 seconds (distance divided by speed and = time)