The two trains run from two places 770 km apart, The distance between the two trains seven hundred and seventy Km of the two places to each other, a car every hour forty-five Km, B per hour forty-one thousand Mi, car B starts first two After a few hours, car a started. Car a met car B a few hours later No equations
(770-41×2)÷(45+41)
=688÷86
=8 (hours)
A. The distance between B and a is 1200 km. A and B trains leave from a and B at the same time. The speed of train a is 40 km / h, and that of train B is 40 km / h
At the time of departure, a pigeon flew out of the carriage and flew to train a at a speed of 80 km / h. When the pigeon met train a, how far was train B from ground a
When a pigeon meets a car, it needs to:
1200 ÷ (40 + 80) = 10 hours
B distance a:
1200-B speed × 10
B. I don't know the speed. Take a look and calculate for yourself
An airplane flies 715 kilometers per hour, 13 times the distance traveled by a car per hour. How many kilometers faster is an airplane than a car per hour?
715-715 △ 13, = 715-55, = 660 (km), a: the plane is 660 km faster than the car per hour
The plane flies 480 kilometers per hour, the car travels 60 kilometers per hour, the plane flies 5 / 2 hours, the car travels several hours
Aircraft speed: car speed ratio = 8:1, then the time for the car to travel is 8 * 5 / 2 = 20 hours. I am doing a task