As shown in the figure, ABCD is a simulated runway with a side length of 6 meters. A toy car starts from a and moves clockwise at a speed of 5 cm per second. B toy car starts from the midpoint of CD and moves counterclockwise. As a result, the second time the two cars meet is just at point B. how many cm per second does car B walk?

As shown in the figure, ABCD is a simulated runway with a side length of 6 meters. A toy car starts from a and moves clockwise at a speed of 5 cm per second. B toy car starts from the midpoint of CD and moves counterclockwise. As a result, the second time the two cars meet is just at point B. how many cm per second does car B walk?

ABCD is a 6-meter-long square simulation track. Toy a starts from a and moves clockwise at a speed of 5 cm per second. Toy B goes out from the midpoint of the CD
FA goes counter clockwise. As a result, the second time the two cars meet is at point B. how many centimeters does car B walk per second?
(formula)

The second time to arrive at point B at the same time shows that the time taken by a and B is the same. The distance taken by a is five side lengths, that is, 5 * 6 = 30 meters
The speed of a is 5 cm / S = 0.05 M / s, and the time for a to reach B is 30 / 0.05 = 600 s
B: 5.5 side lengths, that is, 5.5 * 6 = 33m = 3300cm
Then the velocity of B is: 3300 / 600 = 5.5 cm / s

If the model y = AX2 is used to describe the relationship between the sliding distance y m after emergency braking and the braking speed x km / h, it is known that the speed of a certain type of vehicle is 60 km / h
It is known that the speed of a certain type of vehicle is 60km / h, and the taxiing distance after emergency braking is 20m. If the speed limit is 100km / h on the highway, the taxiing distance after emergency braking of a vehicle of this type is 50m, ask whether the vehicle is speeding

y=ax2
20=a*3600
a=1/180
50=1/180*x²
X = 95 no speeding

A car goes from place a to place B at a speed of 45 kilometers per hour,
When he arrived at the midpoint of a and B, he was ordered to have a physical examination for half an hour, so he increased the criminal speed by 15 kilometers per hour, so he just arrived at B as required, and calculated the distance between a and B
Solving linear equation with one variable
Let's be clear. I can't understand that. I can write Chinese characters directly

Suppose the distance between a and B is 2x
X divided by 45 minus x divided by (45 plus 15) equals one in two
If the solution of X is 90, then the distance between a and B is 2x, which is equal to 180 km!
It's over!