Three hours later, the distance between the two vehicles is 40 km. At this time, 80% of the whole journey of vehicle a, 60% of the whole journey of vehicle B and how many meters is the distance between the two cities

Three hours later, the distance between the two vehicles is 40 km. At this time, 80% of the whole journey of vehicle a, 60% of the whole journey of vehicle B and how many meters is the distance between the two cities

The distance between the two cities is x meters
80%X-60%X=40
（80%-60%）X=40
20%X=40
X=40÷20%
X=200

After 4 hours, car a runs 80% of the whole journey, and car B runs 13 kilometers above the midpoint. It is known that car a travels 3 kilometers more per hour than car B. how many kilometers are there between city a and city B?

Let a and B be x km apart, (80% - 12) X-13 = 12, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 2503; answer: A and B are 2503 km apart

After 4 hours, car a runs 80% of the whole journey, and car B runs 13 kilometers above the midpoint. It is known that car a travels 3 kilometers more per hour than car B. how many kilometers are there between city a and city B?

Let a and B be x km apart, (80% - 12) X-13 = 12, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 2503; answer: A and B are 2503 km apart

A train from a station to a station, an average of 120 kilometers per hour, 2.5 hours to arrive. From B station to return to a station, an additional 80 kilometers per hour, find the average speed of the train

150km / h. The average speed is equal to the total distance divided by the total time. The distance between a and B is 120 times 2.5, which is equal to 300. The return time is equal to 300 divided by (120 + 80) which is equal to 1.5. So the average speed is equal to (300 + 300) divided by (1.5 + 2.5) which is equal to 150