A car travels 55 kilometers per hour. It takes seven tenths of an hour from a to B. how many kilometers are there between a and B?

A car travels 55 kilometers per hour. It takes seven tenths of an hour from a to B. how many kilometers are there between a and B?

Encounter = 55 × 7 / 10 = 38.5km

The two cars run from the two places 365 meters apart at the same time. Car a runs 60 kilometers per hour and car B 55 kilometers per hour
A few hours later, the two cars met with a distance of 20 kilometers? (solved by equation)

Set X hours later, the two cars meet with a difference of 20 kilometers
60X+55X+20=365
115X=365-20
115X=345
X=3
A: three hours later, the two cars met with a difference of 20 kilometers

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If the distance of car B is x km at 10 a.m., then the distance of car a is 5x km, then the time of car a driving before 10 a.m. is 5x55 hours, and that of car B is x55 hours. According to the meaning of the question, we can get the equation: 5x55 + 2 = 3 × (x55 + 2), & nbsp; & nbsp; 2x = 220, & nbsp; & nbsp; & nbsp; & nbsp; X = 110, so before 10 o'clock, a's driving time is: 5x55 = 5 × 11055 = 10 (hours), B's driving time is x55 = 11055 = 2 (hours), 10-2 = 8 (hours). A: B starts 8 hours later than a's

Two cars are running from two places 400 kilometers apart at the same time. Three hours later, they are 10 kilometers apart. It is known that one car runs 55 kilometers per hour. How can we find the speed of the other car? (answer in two ways)

Use the arithmetic method: (400-10) △ 3-55, = 390 △ 3-55, = 130-55, = 75 (km / h); use the equation to set the speed of another car as X km / h, (55 + x) × 3 = 400-10, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 55 + x = 390 △ 3, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp