Party A and Party B set out from AB and head for each other. When they met, Party A traveled 55% of the whole journey, 3.5 kilometers more, and Party B just walked 1.2% of the route of Party A How many kilometers did B travel when they met? Don't use complicated equations, especially for quadratic equations with 2 variables. It's better to write the meaning of each step in the formula

Party A and Party B set out from AB and head for each other. When they met, Party A traveled 55% of the whole journey, 3.5 kilometers more, and Party B just walked 1.2% of the route of Party A How many kilometers did B travel when they met? Don't use complicated equations, especially for quadratic equations with 2 variables. It's better to write the meaning of each step in the formula

3.5÷（55%-1/2）×1/2-3.5
=3.5÷5%×1/2-3.5
=70×1/2-3.5
=35-3.5
=31.5km

Car a and car B leave from ab 55 kilometers away at the same time. After driving 23 kilometers, car a meets with car B. after meeting, the two cars continue to move forward,
Q: (1) how many kilometers is the second meeting point from B? (2) how many kilometers is the sixth meeting point from a?
Why does this question need 23 * 3 = 69 to work out the driving distance of the second meeting a? Can you analyze the whole question for me?

(1) When Party A and Party B meet for the second time, the sum of the distances they walk is three times of the distance between AB, so the distance a walks is:
23 * 3 = 69 (km) - because when they first met, the sum of their distance was AB, and a walked 23 km, then when the sum of their distance was three times of AB, a should have walked three 23 km
Therefore, the distance between the second meeting point and B: 23 * 3-55 = 14 (km)
(2) After each additional encounter, the sum of the two people's distance increased by 2 times of AB distance. Therefore, the sum of their distance was 11 times when they met for the sixth time, in which a walked 23 * 11 = 253 (km). 253 / 55 = 4 53 km
Therefore, the sixth meeting point is 53 kilometers away from a

The distance between the two cities is 500 km. A passenger train and a freight train leave the two cities at the same time. The passenger train runs 55 km per hour and the freight train 45 km per hour
Meet in a few hours

500÷（55+45）
=500÷100
=5 (hours)

The distance between a and B is 465km. A bus and a train run from the two places at the same time. The bus runs 74.5km per hour and the truck 55.5km per hour?

(1) (465-75) / (74.5 + 55.5) = 390 ／ 130 = 3 (hours) answer: after 3 hours, the distance between the two vehicles is 75 km. (2) (465 + 75) / (74.5 + 55.5) = 540 ／ 130 ≈ 4 (hours) answer: after 4 hours, the distance between the two vehicles is 75 km