If the engine power is kept unchanged, the speed of the car is v2 What is the maximum speed of the car on the horizontal road with the same amount of power (assuming that the resistance of the car is the same in three cases)?

If the engine power is kept unchanged, the speed of the car is v2 What is the maximum speed of the car on the horizontal road with the same amount of power (assuming that the resistance of the car is the same in three cases)?

When the power of the vehicle is p, the component of gravity on the slope is g, and the maximum speed on the horizontal road is V, then:
P/v1=f+G
P/v2+G=f
Add the two formulas
P/v1+P/v2=2f
v=P/f=2/(1/v1+1/v2)=2v1v2/(v1+v2)
The maximum speed of a car on a level road with the same power is 2v1v2 / (V1 + V2)

A car moving along a slightly inclined slope, if the power of the engine remains unchanged, it can go up the slope at the speed of V1 and go down the slope at the speed of V2, then the maximum speed of the car moving at the same speed on the horizontal road with the same roughness is ()
A. v1v2B. v1+v22C. 2v1v2v1+v2D. v1v2v1−v2

Let p be the power, F1 = mgsin θ + FP = f1v1 for upward uniform motion, F2 + mgsin θ = FP = f2v2 for downward uniform motion, F3 = FP = f3v3 for horizontal motion, and V3 = 2v1v2v1 + V2 for upward uniform motion

What's the ratio between speed and time

In inverse proportion
Because the product of speed and time must be (the product is the distance)
Secondly, these two quantities are variable quantities
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If the time is fixed, what is the ratio between the speed and the distance?
Why?

Proportional. Distance = speed × time