A plane flies between two cities with a wind speed of 24km / h. It takes 2h50min to fly along the wind and 3H to fly against the wind When an aircraft flies between two cities, the wind speed is 24km / h, it takes 2h50min to fly along the wind, and 3H to fly against the wind. The flight speed and the distance between two cities are calculated

A plane flies between two cities with a wind speed of 24km / h. It takes 2h50min to fly along the wind and 3H to fly against the wind When an aircraft flies between two cities, the wind speed is 24km / h, it takes 2h50min to fly along the wind, and 3H to fly against the wind. The flight speed and the distance between two cities are calculated

Let X be the distance between two cities
x/3+24=x/(2+50/60)-24
x=48*51=2448
2448/3+24=816+24=840
Therefore, the windless speed of the plane is 840 km / h, and the distance between the two places is 2448 km

A plane flies between two cities with a wind speed of 24km / h,
It takes 2 hours and 50 minutes to fly with the wind and 3 hours to fly against the wind. How long is the distance between the two cities?

Let the aircraft speed be x km / h,
17/6*（X+24）=3*（X-24）
The solution is x = 840
Then 3 * (840-24) = 2448
A: the speed of the plane is 840 km / h, and the distance between the two cities is 2448 km

When an aircraft flies between two cities, it takes 5 hours and 30 minutes to go downwind and 6 hours to go upwind. The known wind speed is 24km / h, then the downwind speed of the aircraft is (the speed of the aircraft in the upwind is)（

Let the windless speed of the aircraft be X
330(x+24)=360(x-24)
The solution is x = 552
Downwind 576, upwind 528

A plane flies between two cities. The equation of first degree with one variable
When there is no wind, the plane flies 552 kilometers per hour. In a round-trip flight, it takes 5.5 hours to fly with the wind and 6 hours to fly against the wind. Find the speed in the flight and the distance between the two cities

Let the wind speed be x km / h
(552+X)*5.5=6(552-x)
3036+5.5x=3312-6x
11.5x=276
X = 24 km / h
The downwind speed is 552 + 24 = 576
The headwind speed is 552-24 = 528
The distance between the two cities is 6 (552-x) = 3168