It takes two days for a person to walk from city a to city B. on the first day, he takes more than 50% of the whole journey and 72 kilometers. On the second day, the distance is equal to 1 / 3 of the first day What's the distance between the two cities?

Suppose the distance between city a and city B is x km
x·50%+72+（x·50%+72）·1/3 = x
The solution is: (0.5x + 72) · 4 / 3 = X
0.5x+72=0.75x
0.25x=72
x=288
That is, the distance between the two cities is 288 km

A bus from place a to place B traveled one fifth of the whole journey on the first day and 450 kilometers on the second day. At this time, the ratio of the distance traveled to the rest is 3:7

Now we've done the whole process of 3 (3 + 7) = 3 / 10
450÷(3/10-1/5)=4500
A: the distance between Party A and Party B is 4500km

A bus drove from a to B. on the first day, it traveled 1 / 5 of the whole journey, and on the second day, it traveled 450 kilometers,
At this time, the ratio of the distance traveled to the rest is 3; 7. How many kilometers is the distance between a and B

At this time, the ratio of what has been done to the rest of the journey is 3; 7 has been done 3 / 10
Whole course = 450 / (3 / 10-1 / 5) = 4500km

Party A and Party B transport a total of 10.5 tons of goods. The goods transported by Party A are twice as much as those transported by Party B, less than half a ton. How many tons do Party A and Party B transport? Write down the solution

The goods transported by Party A are twice as much as those transported by Party B, less than half a ton,
So it's three times as much as the goods shipped by Party B, less than half a ton,
So the goods transported by Party B: 10.5 + 0.5 / 3 = 11 / 3 (tons)
So 11 / 3 * 2-0.5 = 41 / 6 (tons)

It takes two days for a person to walk from city a to city B. on the first day, he takes more than 50% of the whole journey and 72 kilometers. On the second day, the distance is equal to 1 / 3 of the first day What's the distance between the two cities?