There are two trains, one 180 meters long, 24 meters per second; the other 220 meters long, 26 meters per second Now the two cars are facing each other. How many seconds does it take for the two cars to completely leave?

There are two trains, one 180 meters long, 24 meters per second; the other 220 meters long, 26 meters per second Now the two cars are facing each other. How many seconds does it take for the two cars to completely leave?

Total length = 180 + 220 = 400m
Relative velocity = 24 + 26 = 50 m / S
Time = total length △ relative speed = 400 △ 50 = 8 seconds
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There are two trains, one is 140 meters long, traveling 24 meters per second, and the other is 230 meters long, traveling 13 meters per second. Now the two trains are facing each other. How many seconds does it take for the two trains to meet and leave when they miss?

The length sum of the two trains is: 140 + 230 = 370 (m), the speed is the sum of the two trains' speed, 24 + 13 = 37 (M / s), 370 △ 37 = 10 (s); a: it takes 10 seconds for the two trains to meet and leave when they miss

There are two trains, one is 130m long and the speed is 23m / S; the other is 250m long and the speed is 15m / s. now the two trains are facing each other and it is necessary for them to meet and leave______ s．

According to the meaning of the question, we can get: (130 + 250) △ 23 + 15, = 380 △ 38, = 10 (s)

There are two trains, one 320 meters long, 18 meters per second, and the other 22 meters per second
Ask the conductor of another train

It is (18 + 22) × 15-320 = 280m