If the product of four unequal integers a, B, C and D is equal to 25, how much is a + B + C + D? To write the steps

Because 25 = 5 * 5, it is unlikely that a, B, C and D are all positive numbers, because if they are all positive numbers, there are no more than two cases
1. The two numbers are 5, but the requirements are not equal to each other
2. One of the numbers is 25, but then the other three numbers must all be 1
So we need to take negative integers into account. Because 5 * 5 = 25, if we consider making a 5 negative, it will become 5 * (- 5) = - 25. If we want to make it positive, we need to multiply it by - 1 to get 5 * (- 5) * (- 1) = 25. Finally, if we multiply it by 1, we can get four numbers multiplied by 5 * (- 5) * 1 * (- 1) = 25. Then the sum of these four numbers is of course 0

If the product of a.b.c.d. is equal to 25, then a + B + C + D=____

A. B.c.d. - 1,1,5, - 5, respectively
So a + B + C + D = 0

If the product of four unequal integers a.b.c.d. equals 25, what is the value of a + B + C + D?

A. B.c.d. is - 1,1,5, - 5 respectively, so a + B + C + D = 0

If the product of four unequal integers a, B, C and D is equal to 25, how much is a + B + C + D? To write the steps