for(x=0,y=0;(y=123)&&(x

for(x=0,y=0;(y=123)&&(x

4 times (y = 123) & (x)

x+y=953,x-y=123

What are you doing? Solving equations?
If so:
Solution 1
x+y=953……………… (1)
x-y=123……………… (2)
(1) + (2), there are: 2x = 1076
The solution is: x = 538
Substituting (2), there is: 538-y = 123
The solution is y = 415
The solutions of the original equations are: x = 538, y = 415
Solution 2
x+y=953……………… (1)
x-y=123……………… (2)
(1) + (2), there are: 2x = 1076
The solution is: x = 538
(1) (2), there are: 2Y = 830
The solution is y = 415
The solutions of the original equations are: x = 538, y = 415

X + y + Z = when x = 123, y = 123, z = 123

Yes, x + y + Z = 369 yes, x = 123, y = 123, z = 123