Sequence 1.2.3.4.2012 how many zeros are there in the 2012 numbers

Sequence 1.2.3.4.2012 how many zeros are there in the 2012 numbers

We use X to represent numbers 1 to 9. First, we consider two digits: there can only be one 0, that is, there are nine in the form of x0. Then we consider three digits: when there is one 0, there are nine in the form of xX0 = 81, and nine in the form of x0x = 81. When there are two zeros, there are nine in the form of X00, there are 81 * 2 + 9 * 2 = 180. Next, we consider four digits 10

The fifth number 1,2,8,28, ()
Anyway, I can't push it out. Neither forward nor backward

It's 100
The rule is: the sum of the first number multiplied by 2 and the second number multiplied by 3 is the third number
For example:
（1）*2 +（2）*3 =8
（2）*2 +（8）*3 =28
（8）*2 +（28）*3=100