The complementary angle of alpha is known to be 132 ° 47 ', and the degree of the remainder of alpha is calculated

The complementary angle of alpha is known to be 132 ° 47 ', and the degree of the remainder of alpha is calculated

90°-（180°-（132°+47°/60))=42°47′

The remainder of an angle is 5 / 13 of its complement, which is less than 4 degrees?

Who is less than who?
90-x=(180-x)5/13-4
x=161/4

1. The complementary angle of an angle is 42 ° less than half of the complementary angle of this angle. 2. The complementary angle of an angle is 3 times larger than the complementary angle of this angle. 10. Calculate the degree of these two angles
Solve by equation

1. Let the size of this angle be x ° and its remainder angle be (90-x) °, and its complement angle be (180-x) °
List the equation: 90-x = 0.5 * (180-x) - 42, the solution is x = 84
2. Let the angle be x degree,
List the equation: 180-x = 3 (90-x) + 10
The solution is x = 50