There are five numbers, among which the sum of every four numbers is 21, 22, 23, 24 and 30 respectively?

There are five numbers, among which the sum of every four numbers is 21, 22, 23, 24 and 30 respectively?

（21+22+23+24+30）/4=120/4=30
30-21=9
30-22=8
30-23=7
30-24=6
30-30=0
These five numbers are 9, 8, 7, 6 and 0

There are five numbers, in which the sum of every four numbers is 15, 22, 23, 24 and 32 respectively, and one of them is negative, which is negative
There are five numbers, of which the sum of every four numbers is 15, 22, 23, 24 and 32 respectively. One of them is negative, and this negative number is【
Write the reason,

Negative three

This is a math problem: cm: 22 22.5 23 24 24.5 25 25.5 27 yards: 34 35 36 38 39 40 41 44 If you use X to represent cm

X is centimeter, y is code
Y=2X-10

1/2*4*6+1/4*6*8+------ +1/20*22*24=

There is a formula
1/[n*(n+2)*(n+4)]=1/4{1/[n(n+2)]-1/[(n+2)(n+4)]}
therefore
1/（2*4*6）+1/（4*6*8）+------ +1/（20*22*24）
=1/4[1/(2*4)-1/(4*6）]+1/4[1/（4*6）-1/(6*8)]+------ +1/4[1/（20*22）-1/(22*24)]
=1/4[1/(2*4)-1/(4*6）+1/（4*6）-1/(6*8)+------ +1/（20*22）-1/(22*24)]
=1/4[1/(2*4)-1/(22*24)]
=65/(22*24)
=65/528

According to this rule, what is the number 2002?

The rule is n ^ 2 - 1
So the number 2002 is 2002 ^ 2-1 = 4008003

0,3,8,15,24. What is the number 2002 (Law)

0=0*2
3=1*3
8=2*4
15=3*5
24=4*6
The number of 2002 should be 2001 * 2003 = 4008003

0,3,8,15,24,… Then the number 2003 in this column is

Subtract 1 from the square of 2003

The mathematical problem of finding the law

☆+○+□=140 (1)
☆-○=20 (2)
○-□=15 (3)
From (2) - (3), [- 20 + □ = 5, and then from (1) - this formula, we can get 30 = 135 and 0 = 45
Then [

Several mathematical problems for finding laws
Question 1: 1,4,11,27,61133, (); question 2: 2,5,13,35,97, (); question 3: 16,17,36111448, (); question 4: 1,3,0,6,10,9, (); question 5: 1,2,8,28100, (). 279; 275; 2245; 17; 356

The first question: 1,4,11,27,611332794 = 1 * 2 + 211 = 4 * 2 + 327 = 11 * 2 + 561 = 27 * 2 + 7133 = 61 * 2 + 11279 = 133 * 2 + 132,3,5,7,11,13 are continuous prime numbers. The law is as follows: an + 1 = 2An + F (n) f (n) is the nth prime number. The second question: 5 = 2 * 3-113 = 5 * 3-235 = 13 * 3-497 = 35 * 3-81,2,4,8 are 0 of 2

How to calculate the rule of 0 9 26 65 124
0 9 26 65 124 method

0=1^3-1……
9=2^3+1……
26=3^3-1……
65=4^3+1……
124=5^3-1……
……
s=n^3+（-1）^n