If the position of 17 is (2,3) and 27 is (3,2), then the position of 2011 in this column is (2,3) 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 ••••••••••••••••

If the position of 17 is (2,3) and 27 is (3,2), then the position of 2011 in this column is (2,3) 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 ••••••••••••••••


Location (167,4)
The specific ideas are as follows:
2011 is the number 1006, and each row is 6, which is the number 167 and the number 4
So the location information is (167,4)



There are column numbers 3, 7, 10, 17, 27, 44,... From the third number, each number is equal to the sum of the first two numbers, then the remainder of the 1998 number divided by 5 is
(the question is a little too many words, and the next is: how many


Find them divided by 5, the remainder of the cycle, their remainder must also be the sum of the first two
3,2,0,2,2,4,1,0,1,1,2,3,0,3,3,1,4,0,4,4,3,2,0...
The cycle section is 201998 / 20 = 99 + 18
So 1998 is the same as 18,
It's 0



There is a column of numbers - 12, 25, - 310417 Then the seventh number is______ .


If the numerator of the seventh number is 7 and the denominator is 72 + 1 = 50, then the seventh number is - 750



How to write 2,3,5,9, (), ()?


There should be the following rules:
2 = 1 + 2^0
3 = 1 + 2^1
5 = 1 + 2^2
9 = 1 + 2^3
= 1 + 2^4
So () should be 17



The nth number 0,3,8,15,24 is represented by an algebraic expression containing n


Observation shows that: each item plus 1 is the square of a number, that is, 1,4,9,16,25 = 1 ^ 2,2 ^ 2,3 ^ 2,4 ^ 2,5 ^ 2
So the nth number is n ^ 2-1



The first number is 8, the second number is 13, the third number is 20, and the fourth number is 29. Find n numbers and express them with algebraic formula


Hello, let the nth number be an. According to the meaning of the problem, A1 = 8, A2 = 13, A3 = 20, then an-a (n-1) = 2n + 1, a (n-1) - A (n-2) = 2N-1. A2-a1 = 5, both sides add up to an-a (n-1) + a (n-1) - A (n-2) +... + a2-a1 = 2n + 1 + 2N-1 + 5an-a1 = (n-1) (2n + 1 + 5) / 2An = (n-1) (2n + 6) / 2 + a1an = (n-1) (n + 3) +



1. 3 / 4, 2 / 3, 5 / 8, 3 / 5


2 / 2, 3 / 4, 4 / 6, 5 / 8, 6 / 10
So it's (n + 1) / 2n



Observe 2,5 / 4,10 / 9,17 / 16. Express the nth number with algebraic formula
It's a fraction


(n²+1)/n²



There are several monomials in the algebraic formula 2x + y, 3AB 0y △ x Wu + 2m + n / 2


3



Find the law, 1,3,7,13,21, etc., the algebraic formula of the nth number
The first figure is one point, the second figure is three points, the third figure is seven points, the fourth figure is 13 points, and the fifth figure is 21 points. Try to guess how many points there are in the nth figure


2×(n-1)+1