The following matrix is composed of all odd numbers (1) What is the relationship between the sum of nine numbers in the parallelogram and the number in the middle? (2) If you make any parallelogram box similar to (1) in a number matrix, is there such a rule for the sum of these nine numbers; (3) Can the sum of the nine numbers be equal to 1998? 20051017? If yes, please write down the smallest one of the nine numbers. If not, please give the reason 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 Inside the parallelogram is: 23 25 27 39 41 43 55 57 59

The following matrix is composed of all odd numbers (1) What is the relationship between the sum of nine numbers in the parallelogram and the number in the middle? (2) If you make any parallelogram box similar to (1) in a number matrix, is there such a rule for the sum of these nine numbers; (3) Can the sum of the nine numbers be equal to 1998? 20051017? If yes, please write down the smallest one of the nine numbers. If not, please give the reason 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 Inside the parallelogram is: 23 25 27 39 41 43 55 57 59

The average of 1.9 numbers is the number in the middle
2. Yes, because you can set the number in the middle as 2n + 1,
Then the other numbers are 2n-17, 2n-15, 2n-13, 2N-1, 2n + 3, 2n + 15, 2n + 17, 2n + 19
So the average is still in the middle
3. 1998 can't ~ because the average is 222, which doesn't satisfy the odd number
2005 can not ~ because the average is not an integer
1017 is OK, because the average is 113, not on two sides, so it holds
The smallest number is 113-18 = 95

Arrange 1, 2, 3 from left to right, and get a 2009 digit: x = 123123 12312, find the remainder of X divided by 101

123123123123 / 101 = 1219040823.0
Every 12 can be divisible
2009 / 12 = 167.5
That's 12312
12312 / 101 =121.91

Write 8 on the left side of a three digit number. The number you get is just 51 times of the three digit number. What's the original three digit number

lzx_ 907 ,
Let the original number be X
8×1000＋X＝51X
50X＝8000
X＝8000÷50
X＝160

The remainder of 123456.2930 divided by 11 is

For example, 1518, P = 1 + 1 = 2, q = 5 + 8 = 13, 13-2 = 11, so 1518 can be divided by 11, 2068, P = 2 + 6 = 8, q = 0 + 8 = 8, 8-8 = 0, so 2068 can be divided by 11, OK