There are 249 flowers, arranged in the order of 5 red flowers, 9 yellow flowers and 13 green flowers, and the last one is______ &Flowers of color

249÷（5+9+13）=249÷27=9… After 9 cycles, there are 6 flowers left, so the last one is yellow

Use yellow, red, green and pink beads to arrange in a string. The colors of any four adjacent beads are different. If you want to make the 27th one red, share it on March 1, 2014, as long as you get the right answer

Results: there were 6
1. After the current four are confirmed, the color of the nth from the 5th must be the same as that of the previous nth-4th
2. The 27th one is red, and the third one must be red. There are six different ways to wear 1, 2 and 4

If the number in the box on the right is multiplied by 3, and the number in the box on the left is multiplied by 2, then add up the number, and the sum is 49. Guess which box has an odd number of candy. What do you think?

Shangmiande is right!

The ratio of bags of candy in pile a and pile B is 4:1. Take out 13 bags from pile a and put them into pile B. at this time, the ratio of bags of candy in pile a and pile B is 7:5
The ratio of bags of candy in pile a and pile B is 4:1. Take out 13 bags from pile a and put them into pile B. at this time, the ratio of bags of candy in pile a and pile B is 7:5. How many bags did each pile of candy have

The total remains unchanged
It turns out that a is the total number: 4 (4 + 1) = 4 / 5
Now a is the total: 7 (7 + 5) = 7 / 12
4 / 5-7 / 12 = 48 / 60-35 / 60 = 13 / 60
The total number is: 13 △ 13 / 60 = 60 bags
Original A: 60 × 4 / 5 = 48 bags
Original B: 60-48 = 12 bags
Suppose that a has 4x bags and B has x bags
（4x-13）：（x+13）=7：5
7（x+13）=5(4x-13)
7x+91=20x-65
20x-7x=91+65
13x=156
x=12
Original A: 12 × 4 = 48 bags
Original B: 12 bags
If you don't understand, please ask

Two boxes are filled with fruit candy. One box has an odd number of candy, and the other box has an even number of candy. If the number of candy in box a is multiplied by 3, then Box B is filled with fruit candy

Is the number of candy in box a multiplied by 3 or odd
Whether the candy in Box B is multiplied by an odd number or even number, it must be even as long as it is not multiplied by zero. Adding and subtracting odd numbers is odd, and adding and subtracting even numbers is even~

There are fruit candy in both boxes. The number of candy in one box is odd, and the number of candy in the other box is even
If you multiply the number of sweets in the box on the right by 3, multiply the number of sweets in the box on the left by 2, and then add up, the sum is 49. Guess which box has an odd number of sweets?

Odd × odd = odd
Odd × even = even
Even × even = even
Right × 3 + left × 2 = 49 is odd,
So, the number of candy in the box on the right is odd

The ratio of the number of balls in box a and Box B is 4:1. If seven balls are taken from box a and put into Box B, the ratio of the number of balls in box a and Box B becomes 5:3, and the total number of balls in two boxes is calculated

Suppose box a contains 4x balls, then Box B contains x balls
Listed by the equation,
4X-7:X+7=5:3
The solution is x = 8
4x8 + 8 = 40
There are 40

The ratio of small balls in box a and Box B is 7:4. After 93 balls are taken out of box a and 42 balls are taken out of Box B, they have the same number of small balls left
How many are there in two boxes a and B
There should be analysis

Let a have 7x, then B have 4x
7x-93=4x-42
3x=93-42=51
The solution is x = 17,
The number of a was 17 * 7 = 119, and that of B was 17 * 4 = 68
Count:
If the ratio of the number of small balls is 7:4, then a is more than B (7-4) / 4 = 3 / 4
There are 93 in box a and 42 In Box B, so there are 93-42 more in box a than in Box B = 51
That is to say, 3 / 4 of B is 51, so B has 51 (3 / 4) = 68
A has 68 + 51 = 119
A: there were 119 in a and 68 in B

If one fifth of the total number of balls is taken out of box a, the number of balls in box a and Box B is different,
If one fourth of the total number of balls is taken out from Box B, the number of balls taken out twice is exactly the same. Then which box has the most balls? What do you think?

A. one fifth of a is equal to one fourth of B. let a have 5x, B have 4x, and 5x > 4x

Put nine identical balls into three different boxes, and each box should have at least one ball. If the number of balls in each box is different, there are ()
A. 15 species B. 18 species C. 19 species D. 21 species

First, consider that each box has at least one small ball, using the baffle method, 9 balls with 8 empty in the middle, insert two plates, there are a total of C28 = 28 kinds, in which each box has the same number of small balls, there is one way to put; two boxes have the same number of small balls, including: 1, 1, 7; 2, 2, 5; 4, 4, 1, each has 3 ways to put, a total of 9 ways to put, so different ways to put a total of 28-1-9 = 18 Therefore, B

There are 249 flowers, arranged in the order of 5 red flowers, 9 yellow flowers and 13 green flowers, and the last one is______ &Flowers of color