Five cups are put in the tray mouth down. Turn two cups at a time. Can he turn five cups mouth up

Five cups are put in the tray mouth down. Turn two cups at a time. Can he turn five cups mouth up

Absolutely not, because 5 is an odd number, 3 is also a multiple of 4, it can't be a multiple of 3, and the decomposition of 5 is 2 and 3, 1 and 4, so it's impossible

Five meters minus a few decimeters is two meters

30 decimeters, 10 decimeters = 1 meter

71 times 69, how to use the multiplication formula to calculate, (x-4) (x + 4) (the second power of X + 16)
How to do the quadratic power of (3m + 2n) - (2m + 3n)

﹙1﹚71×69＝﹙70＋1﹚×﹙70－1﹚＝70²－1²＝4900－1＝4899；﹙2﹚﹙x－4﹚﹙x＋4﹚﹙x²＋16﹚ ＝﹙x²－16﹚﹙x²＋16﹚ ＝x^4－16² ＝x^4－256﹙3﹚﹙3m＋2n﹚²－﹙2...

A simple algorithm of 1999 times 0.5, 1997 times 0.3 and 1999 times 1.2

1997×0.3/1999×0.5+1.2/1999
=1997×0.6/1999×0.5+2×0.6/1999
=（1997+2）×0.6/1999
=0.6
As a student sister, I hope children's shoes will continue to work hard in mathematics! >_

A simple algorithm of 10.3 × 99 + 10.3

10.3×99+10.3
=10.3×（99+1）
=10.3×100
=1030.

1+2+3+4+… +A simple algorithm of 99

1+2+3+4+… +99
＝（1＋99）×99÷2
＝100×99÷2
＝9900÷2
＝4950

3.37 * 0.99 simple algorithm

3.37*0.99
=3.37*(1-0.01)
=3.37*1 - 3.37*0.01
=3.37-0.0337
=3.3363


What's the simple algorithm of 11 times 11?

Pull at both ends and add in the middle
11*11=121
Hundred: 1, ten: 1 + 1 = 2: 1
11*12=132
Hundred: 1, ten: 1 + 2 = 3: 2

A simple algorithm of multiplying 36.4 by 11 and subtracting 36.4

36.4×11-36.4
=36.4×（11-1）
=36.4×10
=364

There are several fast algorithms for the product of 48 times 125 times 25

48*125*25
=8*125*6*25
=1000*150
=150000