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1-x/(1+x+x²)+6/(1-x)=7/(1-x) 1-x/(1+x+x²)=1/(1-x) 両辺に同時に乗じ(1-x)(1+x+x²) 1-x³-x(1-x)=1+x+x² x³+2x=0 x(x²+2)=0 x=0
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