3/2x+2/1/7x+x=33

3/2x+2/1/7x+x=33

(2x/3)+(x/2)+(x/7)+x=33
そうなの?
x*[(2/3)+(1/2)+(1/7)+1]=33
x*(2*2*7+3*7+6+2*3*7)/(2*3*7)=33
x*(28+21+42)/42=33
x=33*42/91=198/13