The two trains leave from a and B and meet at 48km from the midpoint after 4 o'clock. The speed of the slow train is five seventh of that of the fast train. What are the speeds of the fast train and the slow train?
Express speed
48×2÷4÷(1-5/7)
=24÷2/7
=84 km / h
Slow speed 84 × 5 / 7 = 60 km / h
A. The distance between B and B is 630 kilometers. A and B start from a and B at the same time, and run in opposite directions. After 9 hours, they meet. It is known that the speed ratio of a and B is 7:3
How many kilometers does a travel more than B when they meet
Solution 1: 630 △ 9 = 70km (the sum of the speed of a and B is 70km)
Because the speed ratio of a and B is 7:3. We divide 70 km into 10 parts, 7 parts for a and 3 parts for B
The speed of a is 7 × 7 = 49 km, and that of B is 7 × 3 = 21 km
The speed difference is 49-21 = 28 km
Distance difference 28 × 9 = 252km
The speed ratio of car a and car B is 4 to 7. The two cars are going from two places at the same time. They meet 15 kilometers away from the destination. How much is car B
It is known that the speed ratio of car a and car B is 4:7. When they meet, car a runs 4 / (4 + 7) = 4 / 11 of the whole journey and car B runs 7 / (4 + 7) = 7 / 11 of the whole journey