First: the worker's uncle saws a 1-meter-high cylindrical timber, which is divided into two parts along the diameter of the bottom surface. At this time, the surface area increases by 0.8 square meters. Find the original surface area of the timber The second: a section of iron sheet sewer is 2.5 meters long, with a bottom radius of 1. 2 cm at the joint. How many square meters of iron sheet should be used to make this section of sewer? We are optimistic about the unit, if you can talk about why to do so

First: the worker's uncle saws a 1-meter-high cylindrical timber, which is divided into two parts along the diameter of the bottom surface. At this time, the surface area increases by 0.8 square meters. Find the original surface area of the timber The second: a section of iron sheet sewer is 2.5 meters long, with a bottom radius of 1. 2 cm at the joint. How many square meters of iron sheet should be used to make this section of sewer? We are optimistic about the unit, if you can talk about why to do so

After sawing, two sections are added, viz. VZ = 2 * (2R * h) = 2 * 2R * 1 = 0.8R = 0.8 / 4 = 0.2 (m) VT = 2 π R * H = 2 * 3.14 * 0.2 * 1 = 1.256 (M2) 1

Financial accounting calculation exercises, help me see how to solve
D Co., Ltd. purchased 2 million shares of P company at the price of 15 yuan per share on June 10, 2011 (including the declared but not yet paid cash dividend of 0.2 yuan) and confirmed them as available for sale financial assets. It also paid relevant taxes of 120000 yuan. On June 15, it received the cash dividend of R company in full. On December 31, 2011, the fair value of the shares was 16.8 yuan
Requirements: accounting treatment of D company's related stocks

June 10, 2011
Debit: financial assets available for sale - cost 29.72 million
Dividend Receivable 400000
Loan: bank deposit 30.12 million
June 15th
Debit: bank deposit 400000
Loan: 400000 dividends receivable
December 31, 2011
Debit: available for sale financial assets - fair value change 3.88 million yuan
Loan: capital reserve - other capital reserve 3.88 million
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Help me to see if it's right
A car consumes 85.5 kg of fuel when it runs 410 km in the first day, 97.7 kg when it runs 500 km in the second day, and 76.8 kg when it runs 390 km in the third day. How many kg of fuel does a car consume per km in three days?
(7.8) △ 390 + 410.8 (kg)

That's right