간소화:(b-c)/(a^2-ab-ac+bc)+(c-a)/(b^2-bc-ab+ac)+(a-b)/(c^2-ac-bc+ab) 간소화: (b-c)/(a^2-ab-ac+bc)+(c-a)/(b^2-bc-ab+ac)+(a-b)/(c^2-ac-bc+ab)

간소화:(b-c)/(a^2-ab-ac+bc)+(c-a)/(b^2-bc-ab+ac)+(a-b)/(c^2-ac-bc+ab) 간소화: (b-c)/(a^2-ab-ac+bc)+(c-a)/(b^2-bc-ab+ac)+(a-b)/(c^2-ac-bc+ab)

하나씩 나 누 어 a&sup 2;-ab-ac+bc=(a-b)(a-c)b²-bc-ab+ac=(b-a)(b-c)c²-ac-bc+ab=(c-a)(c-b)그래서 원 식=(b-c)/[(a-b)(a-c)]+(c-a)/[(b-c)]+(a-b)/[(c-a)(c-b)]=[(a-c)-(a-b)]/[(a-b)(a-c)]+[(b-a)--(b-c)...