알려진 x 3 . 4 . 5 . xy+yz+zx x2 +y2 +z2의 값입니다 .

알려진 x 3 . 4 . 5 . xy+yz+zx x2 +y2 +z2의 값입니다 .

0

x^2+y^2+y^2z+yz^2+z^2+z^2+zx^2+zx^2+3xxyz=k ( xy+z+z )

x^2+y+yz^2+z^2+zx^2+xx^2+xxx^2+xxxxx^2+xxxxxxxxxxxxxx+xxxxxxxxxxxxxx^2+y+y+xxxxxxxxxy+y+y+xxxxxxxxxxxxxxxxxxxxxx+y+xxxxxxxxxxxxxxxxxxxxxxxxxxxxy+zy+y+xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxy+y+y+y+y+xxxxxxxxx+x+x+x+x+x+x+x+x+x+x+x+x+xxxxxxxxxxxx+x+x+x+x

x+y+z+z+zx=11 , x^3+y^3+z^3-3xyzx

( x+y+z ) 2
x2 +y2z2 +2 ( xy+yz+zx ) =36
x2+y2+ z2-22-22-22=14
X3 +y3z3+z3-3xyzyz=3xyz=3xyzxyz=3xyz=3x3+y+zyzy+3xyz=3xyzyzy+3xyzyzyzy+3xyzyzy+3xy+3xyxyzyzyzyzy+3xy+3xyxy+3xyzyxyxyzyzyzyzy+zzzzyzyzy+zy+zy+zy+zzzzy+zyzy+3x3xyzzzy+3x3xyzyzyzyzyzyzyzyzy+3xy+3xy+3xy+3x3x3x3x3x3x3x3x3xy+3x3x+3xy+zy+zyzyzyzyzyzyzy+zy+zyz
( X3+3x2y+y3xy2+z3 ) - ( 3xy+3x2y+3y2y2 )
( x+y ) 3+z3은 -3xyxy+z입니다
( X+y+z ) ( x2+y2xy+z+z2 ) -3xy+z2 )
( X+y+z ) ( x2+z2+xy2xy+xxy-zyz )
( X+y+z ) ( x2+y2-z-y-z-z-z-x )
IMT2000 3GPP2

x=xy/x+y+y+zy+z+x+x=x=x+x=x+x+x=x+x=x입니다

( x+y ) / ( xy ) // ( xy ) // ( xy ) //y ( y+z ) =2 ( y+z ) / ( 1/y )

xyz=x+y+z=x+y^2+z^2z^2+z^2z=16x+16+z=1+ ( yz+2x+2x ) + 1+zy+2y2yx + 1 )

z=2x-y1/ ( xy+2z ) = ( xy+4-2y ) = 212 ( x-2 ) , ( y-2 ) = 1/y+z+2 ) ,

함수 f ( x ) = ( a^2 ) x^2+ ( a-1 ) x+3a+1 ) 이 루트값인 경우 a가 0일 때 ,

함수 f ( x ) = ( a^2 ) x^2 + ( a-1 ) ^2 + ( a-1 )
x^2+ ( a-1 ) x+1은 항상 0보다 크거나 같습니다
a ^ ( 0 ) = ( a-1 ) ^ ( a+1 ) = ( a-1 ) 2-8 ( a-1 )
해결책 1 .