The first line is 1. The second line is 2, 3 and 4. The third line is 3, 4, 5, 6 and 7. The fourth line is 4, 5, 6, 7, 8, 9 and 10. Q: what's the sum of line 200?
law:
The first number in line n starts from n, with a total of 2N-1 numbers
Sum of the nth row = n + (n + 1) + (n + 2) +... + (n + 2n-2)
=n(2n-1) +(1+2+...+2n-2)
=n(2n-1)+(2n-2)(2n-1)/2
=4n²-4n+1
=This method can calculate the sum of any row
The sum of line 200 = (2 × 200-1) 178; = 399 & # 178; = 159201
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