Solving equation (x ^ 2 + 1) ^ 2-x ^ 2 = 3

(x^2+1)^2-x^2=3
x^4+2x^2+1-x^2-3=0
x^4+x^2-2=0
(x^2+2)(x^2-1)=0
X ^ 2 = 1 or x ^ 2 = - 2
Because the square of any number is greater than or equal to zero
Therefore, x ^ 2 = - 2 does not conform to the theme
So x ^ 2 = 1
x=±1

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