How many pairs of integers x and y satisfy the equation y ^ 4 + 2x ^ 4 + 1 = 4x ^ 2 * y?

y^4+2x^4+1=4x^2y
y^4-2y^2+1+2(x^4-2x^2y+y^2)=0
(y^2-1)+(x^2-y)=0
y^2=1,x^2=y
Y1 = 1, y2 = - 1, (when y = - 1, x ^ 2-y cannot be equal to 0, so, rounding)
x1=1,x2=-1
So, the real number pair is (1,1), (- 1,1)

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