Please use the equation of one variable to solve it It has been carrying 260 tons of cargo and 1000 cubic meters of volume. Now it is carrying both goods a and B. It is known that the volume of goods a is 8 cubic meters per ton and that of goods B is 2 cubic meters per ton. In order to make full use of the carrying capacity and volume of the ship, how many tons of goods a and B should be loaded respectively?
Suppose a x tons, B (260-x) tons
8x+2(260-x)=1000
260-x=180
x=80