Observe the following problem-solving process, solve the equation x + 2 of x-x + 1 of 1 = 1, multiply both sides of the equation by (x + 2) (x + 1), get x (x + 1) - (x + 2) = 1 The square of x = 3, x = ± 3, is the root of the original equation. Please point out the mistakes in the above steps and write out the correct solution process

Observe the following problem-solving process, solve the equation x + 2 of x-x + 1 of 1 = 1, multiply both sides of the equation by (x + 2) (x + 1), get x (x + 1) - (x + 2) = 1 The square of x = 3, x = ± 3, is the root of the original equation. Please point out the mistakes in the above steps and write out the correct solution process

The first step is wrong
Since both sides are multiplied by (x + 2) (x + 1),
How can the right side still be 1?
What is right is:
We get x (x + 1) - (x + 2) = (x + 2) (x + 1)
x²+x-x-2=x²+3x+2
3x=-4
x=-4/3
After examination
Will you?